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Difference between revisions of "Round Earth Theory Curvature Calculations"

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1. d1 = sqrt(h0^2 + 2 * R * h0)
 
1. d1 = sqrt(h0^2 + 2 * R * h0)
  
Next, we place d1 in the following equation to find the amount hidden behind the alleged curvature of the earth (h1):
+
Next, we place d1 in the following equation to find the amount hidden below the horizon of the earth (h1):
  
 
2. h1 = sqrt((d0 - d1)^2 + R^2) - R
 
2. h1 = sqrt((d0 - d1)^2 + R^2) - R

Revision as of 00:06, 12 July 2018

Manually Calculating the Amount Hidden by Curvature

In order to calculate the amount hidden we may use the Theory of Pythagoras.

Calc-method.png

Diagram Credit: dizzib | Theory Credit: Pythagoras

Important Equations

To find the distance from the observer's eye to the horizon (d1) we first perform the following:

1. d1 = sqrt(h0^2 + 2 * R * h0)

Next, we place d1 in the following equation to find the amount hidden below the horizon of the earth (h1):

2. h1 = sqrt((d0 - d1)^2 + R^2) - R

Example 1: Sea Level

To calculate the amount hidden at sea level, over 6.23 miles, with an observer height of 32 inches, we convert to a like unit (ie. km) and perform the following:

R = 6371 km
h0 = 0.0008128 km (32 inches)
d0 = 10.02621 km (6.23 miles)

1. d1 = sqrt(0.0008128^2 + 2×6371×0.0008128) = 3.21818
2. h1 = sqrt((10.02621 - 3.21818)^2 + 6371^2) - 6371 = 0.00363752

0.00363752 km converted to feet = 11.93412073491 feet hidden

Example 2: Lake Above Sea Level

To calculate the amount hidden across a lake with an altitude of 1368 meters above sea level, we make a slight adjustment to R and perform the following:

R = 6372.368 km (6371 km + 1368 m)
h0 = 0.0008128 km (32 inches)
d0 = 10.02621 km (6.23 miles)

1. d1 = sqrt(0.0008128^2 + 2×6372.368×0.0008128) = 3.21853
2. h1 = sqrt((10.02621 - 3.21853)^2 + 6372.368^2) - 6372.368 = 0.00363636

0.00363636 km converted to feet = 11.93031496063 feet hidden